The DC voltage $V_6$ is obtained as:
\begin{equation} V_{6}=\frac{- R_{a} V_{N} + R_{b} V_{P}}{R_{a} + R_{b}}\,\left[ \mathrm{V}\right] \end{equation}The DC solution of the network is:
\begin{equation} \left[\begin{matrix}Io_{N1}\\I_{V1}\\I_{V2}\\V_{1}\\V_{2}\\V_{3}\\V_{4}\\V_{5}\\V_{6}\end{matrix}\right]=\left[\begin{matrix}0\\\frac{- V_{N} - V_{P}}{R_{a} + R_{b}}\\\frac{- V_{N} - V_{P}}{R_{a} + R_{b}}\\V_{P}\\\frac{- R_{a} V_{N} + R_{b} V_{P}}{R_{a} + R_{b}}\\- V_{N}\\\frac{- R_{a} V_{N} + R_{b} V_{P}}{R_{a} + R_{b}}\\\frac{- R_{a} V_{N} + R_{b} V_{P}}{R_{a} + R_{b}}\\\frac{- R_{a} V_{N} + R_{b} V_{P}}{R_{a} + R_{b}}\end{matrix}\right] \end{equation}Go to VampBiasNullor_index
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Last project update: 2024-10-20 16:54:18